Question 14. NCERT Solutions for Class 11 Chemistry Chapter 1 pdf free download. Answer: Question 31. Hence,C02 produced = 22 g.(iii) Here again, dioxygen is the limiting reactant. Question 6. Answer: (i) 1 mole of C2H6 contains 2 moles of carbon atoms A flask P contains 0.5 mole of oxygen gas. Question 7. Number of oxygen atoms is 18 g of water = 6.02 x 1023. How are 0.50 mol Na2C03 and 0.50 M Na2C03 different? Calculate the molecular mass of the following: NCERT Chemistry – Class 11, Chapter 1: Some Basic Concepts of Chemistry “Some Basic Concepts of Chemistry” is the first chapter in the Class 11 Chemistry syllabus as prescribed by NCERT . (ii) Leaving the exact number (5), the second term has 4 significant figures. Students who are in Class 11 or preparing for any exam which is based on Class 11 Chemistry can refer NCERT Book for their preparation. Question 13. Hence, B is the limiting reagent while A is the excess reagent. The NCERT Class 11th Chemistry textbooks are well known for it’s updated and thoroughly revised syllabus. (b) 1 gram atom of N = 14g; NCERT Solutions For Class 11 Chemistry Chapter 1: In CBSE Class 11 Chemistry Chapter 1, students will learn about the role played by chemistry in different dimensions of life.CBSE students who are looking for NCERT Solutions For Class 11 Chemistry Chapter 1 can refer to this article. Answer: Question 25. (b) Gram atom in 1.4 grams of nitrogen (Atomic mass Mg = 24, N = 14) NCERT Chemistry Chapter 1 Some Basic Concepts of Chemistry Notes for Class 11 by Selfstudys are best notes because these are prepared by experienced staff members. Answer: Question 4. Classification of Elements and Periodicity in Properties . Long Answer Type Questions The stoichiometric coefficients are 1, 3 and 2 respectively. NCERT Solutions for Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry - Free PDF. Question 15. Answer: 1 mole of Mn02, i.e., 55 + 32 = 87 g Mn02 react with 4 moles of HCl, i.e., 4 x 36.5 g = 146 g of HCl. Moving with the chapter, students will find details about the nature of material and chemical laws of combination. Question 11. (iii) In the given addition, the least number of decimal places in the term is 4. Answer: (i) 34.2 (ii) 10.4 (iii) 0.0460 (iv) 2810. IIT JEE Notes; NEET Notes; NCERT Solutions. Which one of the following will have largest number of atoms? Sorry!, This page is not available for now to bookmark. Question 7. Students can download and use these Notes of Chemistry Class 11 Chapter 1 to score good marks in exams. Answer: Molar mass of Ar = 35.96755 x 0.00337 + 37.96272 x 0.00063 + 39.96924 x 0.99600 = 39.948 g mol-1. Before we get into Some Basic Concepts of Chemistry Class 11, it is vital to get the basic knowledge about the chapter. Question 10. Writing the empirical formula of the compound. (i) 28.7 pm (ii) 15.15 µs (iii) 25365 mg (v) 500.0 (vi) 2.0034 Observe each and every step to know the logic behind NCERT solutions of Chemistry Class 11 1st Chapter then you can able to answer any type of question in the exam. Chemical Bonding and Molecular Structure. Calculate the empirical formula. 2 mol of HCl, i.e., 2 x 36.5 g = 73 g HCl react completely with CaC03 = 1 mol = 100 g, Question 36. Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040. Answer: Question 7. Here we have given NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry. 4 HCl (aq) + Mn02 (s) ———–> 2 H2O (l) + MnCl2(aq) +Cl2(g). Answer: Molality is defined as the moles of solute per kilogram of solvent. Chapter 1. A sample of drinking water was found to be severely contaminated with chloroform, CHCly supposed to be carcinogenic in nature. Question 3. How many grams of HCl react with 5.0 g of manganese dioxide? The empirical formula of the compound = C3H4O4. (iii) 100 atoms of A + 100 molecules ofB Question 32. Hence, the answer should have 4 significant figures. Answer: Question 8.What is the molecular mass of a substance each molecule of which contains 9 atoms of carbon, 13 atoms of hydrogen and 2.33 x 10-23 g other component? Question 12. Name two factors that introduce uncertainty into measured figures. Answer: We know that, 1 min = 60 s Download Latest (2018-19) Edition – NCERT Chemistry Books for Class 11 & 12 (Part I and II ), English Medium Calculate the quantity of NaCl in 10 mL of the solution. (ii) Molecular mass of CO2= 12.01 amu + 2 x 16.00 amu = 44.01 amu Along with NCERT sols, books for revision, assignments – solved and unsolved, notes and special notes for the coming CBSE exams for 2020 – 2021. Answer:  (a) 1 gram atom of Mg = 24g Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:(i) N2 (g) + 3H2(g) —–> 2NH3 (g) Answer: Question 34. CBSE Class 11 Chemistry Chapter 1 NCERT Solutions. A compound on analysis was found to contain C = 34.6%, H = 3.85% and O = 61.55%. of this welding gas is found to weigh 11.6 g. Calculate (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula. Answer: Question 3. Answer:  (i) The least precise term has 3 significant figures (i.e., in 0.112). Hence, B is the limiting reagent. Question 20. NCERT Solutions For Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry Chapter-wise Subtopics Chemistry is undoubtedly an important subject that science students need to take seriously. This Class 11 Chemistry Index page contains all the topics that fall under each chapter of the class 11 chemistry syllabus as per the NCERT textbook. The density of water at room temperature is 1.0 g/mL. Therefore,C02 produced from the combustion of 1 mole of carbon = 44 g.(ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant. The total numbers of figures in a number including the last digit whose value is uncertain is called number of significant figures. KCl03 on heating decomposes to give KCl and 02. What is the S.I. Calculate the amount of carbon dioxide that could be produced when Question 27. Here you will find both English and Hindi medium books to download. (iv) 5 mol A + 2.5 mol B Step 2. or one ‘u’? (ii) Skill of the person making the measurement. Students who are in Class 11 or preparing for any exam which is based on Class 11 Chemistry can refer NCERT Book for their preparation. Answer: Question 16. Answer:  1 molecule of oxygen (O2) = 2 atoms of oxygen (Atomic mass of Cu= 63.5 amu) NCERT Book for Class 11 Chemistry Chapter 1 Some Basic Concepts Of Chemistry is available for reading or download on this page. NCERT Solutions for Class 11 Chemistry Chapter-1 Some Basic Concepts of Chemistry Law of chemical combination, Atomic & molecular mass, Mole concept, Determination of molecular formulae, Stoichiometry, Concentration terms.There are a large number of … The simplest whole number ratios of the different elements are: C:H:O::3:4:4 For example, N2(g) + 3H2(g) ———–> 2 NH3(g) Answer: The digits in a properly recorded measurement are known as significant figures. (i) 0.0025 (ii) 208 (iii) 5005 (iv) 126,000 Question 24. (v) 2.5 mol A + 5 mol B Pressure is determined as force per unit area of the surface. Download NCERT Chemistry books for class 11 and 12 standards (Part 1 and 2). The following data were obtained when dinitrogen and dioxygen react together to form compounds: Question 2. .•. produced from the combustion of 1 mole of carbon = 44 g. (ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant. Chapter 4. If the density of methanol is 0.793 kg L -1, what is its volume needed for making 2.5 L of its 0.25 M solution? Answer: The compound is glucose. Answer: (a) Fixing the mass of dinitrogen as 28 g, masses of dioxygen combined will be 32,64, 32 and 80 g in the given four oxides. Calculate no. Answer: The coefficients of reactant and product involved in a chemical equation represented by the balanced form, are known as stoichiometric coefficients. Answer: Four. Number of C02molecules in 11.2 litres. Some Basic Concepts of Chemistry . Round up the following upto three significant figures: Match the following prefixes with their multiples: Free Download. left unreacted. (i) In air, combustion is complete. Question 1. Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. What is the SI unit of molarity? Answer:  1 mole of CuS04 contains 1 mole (1 g atom) of Cu, Molar mass of CuS04= 63.5 + 32 + 4 x 16 = 159.5 g mol-1, Thus, Cu that can be obtained from 159.5 g of CuS04 = 63.5 g. Question 8. Answer: The balanced equation for the combustion of carbon in dioxygen/air is unit of pressure, pascal, is as shown below:1 Pa = 1 Nm-2.If mass of air at sea level is 1034 g cm-2,calculate the pressure in pascal. Chemistry Class 11 Chapter 1 - Some Basic Concepts of Chemistry. All NCERT LECTURE in videos , text and pdf download CLASS 9 to 12, NCERT VIDEO LECTURES FOR CLASS 11 CHEMISTRY CHAPTER 1 Download Hence, the answer should have 3 significant figures. Answer: Question 13. Answer: Empirical formula mass of Fe203 = 2 x 55.85 + 3 x 16.00 = 159.7 g mol–1. Question 3. Determine the empirical formula of an oxide of Iron which has 69.9 % iron and 30.1 % dioxygen by mass. CaC03 (s) + 2HCl (aq) ———->CaCl2 (aq) +C02(g) +H2O(l). (ii) 1 mole of carbon is burnt in 16 g of dioxygen. What is the volume of 02 at N.T.P liberated by 0.1 mole of KCl03? Answer: This is due to the presence of dust particles. What do you mean by significant figures? Structure of Atom . What is the number of significant figures in 1.050 x 104? Class 12; Class 11; Class 10; Class 9; Revision Notes. Question 2. (iv) 2.5 mol of B will react with 2.5 mol of A. India’s No. Question 2. 14g of N = 1 gram atom 1 Answer: Question 4. Answer: 0.5 ml of NaOH means 0.5 mole (20.0 g) of NaOH, 0.5M of NaOH means that 0.5 mole (20.0g) of NaOH are dissolved in 1L of its solution. 3 moles of C2H6 will C-atoms = 6 moles NCERT Books Class 11 Chemistry: The National Council of Educational Research and Training (NCERT) publishes Chemistry textbooks for Class 11. Give an example of a molecule in which the ratio of the molecular formula is six times the empirical formula. Hence, 10 volumes of H2 will react completely with 5 volumes of 02 to produce 10 volumes of water vapour. II. (iii) Number of molecules of ethane 50 M Na2C03 means 0.50 mol, i.e., 53 g Na2C03 are present in 1 litre of the solution. Which of the two flasks contains greater number of oxygen atoms? Class VI-VIII CBSE Classes; Study Material. (a) Mass of 2.5 gram atoms of magnesium, Question 12. Question 9.Calculate the atomic mass (average) of chlorine using the following data: Answer: The chemical equation for the decomposition of KCl03 is. Chlorine is prepared in the laboratory by treating manganese dioxide (Mn02) with aqueous hydrochloric acid according to the reaction. Express the following in scientific notation: or 1 u = 1/12 th mass of an atom of carbon 12. Gram molecular mass of (C12H22O11) = 12 x 12 + 22 x 1 = 16 x 1= 144 + 22 + 176 = 342 g Question 1. NCERT Class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry solutions. Shaalaa has a total of 1 questions with solutions for this chapter in Class 11 Chemistry. Hence, molecular formula is same as empirical formula, viz.,Fe203. (i) H20(ii) C02(iii) CH4, Answer:  (i) Molecular mass of H2O = 2(1.008 amu) + 16.00 amu=18.016 amu Calculate the total number of electrons present in 1.6 g of methane. What is one a.m.u. Another flask Q contains 0.4 mole of ozone gas. Use the data given in the following table to calculate the molar mass of naturally occurring argon. .•. Calculate the mass percent of different elements present in sodium sulphate (Na2 SO4). NCERT Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry Revision Notes contains very easy language which helps the students to study and revise syllabus with almost no time. How many significant figures should be present in the answer of the following? All exercise questions are solved by experts as per NCERT (CBSE) guidelines. Chapter 2. (i) 0.0048 (v) 6.0012 (ii) 234,000 (iii) 8008 (iv) 500.0 3 moles of C2H6 will contain H-atoms = 18 moles. Vedantu provides you with Class 11 Chemistry NCERT Solutions Chapter 1. Answer: Molar mass of Na2C03= 2 x 23 + 12 + 3 x 16 = 106g mol-1 0.50 mol Na2C03 means 0.50 x 105 g = 53 g 0. 1000 mL of 0.75 M HCl contain HCl = 0.75 mol = 0.75 x 36.5 g = 24.375 g Answer: Question 35. NCERT Solutions for Class 11 Chemistry in PDF form to free download. If you have any query regarding NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry, drop a comment below and we will get back to you at the earliest. Define molality. unit of mass is kilogram (kg). All Chapter 1 - Some Basic Concepts of Chemistry Exercises Questions with Solutions to help you to revise complete Syllabus and boost your score more in examinations. Molality of a solution does not depend on temperature. 10 ml of a solution of NaCl containing KCl gave on evaporation 0.93 g of the mixed salt which gave 1.865 g of AgCl by reacting with AgN03solution. CHEMISTRY NOTES FOR CLASS 11 CHEMISTRY DOWNLOAD IN PDF. 1.4g of N = 1/14 x 1.4 = 0.1 gram atom. How many molecules are there in a drop of water if its volume is 0.05 mL? Calculate the concentration of nitric acid in moles per litre in a sample which has a density 1.41 g mL-1 and the mass percent of nitric acid in it is being 69%. Conversion factor =60 s/(1min) (v) 2.5 mol of A will react with 2.5 mol of B. Benefits of Chemistry Notes for Class 11 Chapter 1. Know CBSE 11th Class Chemistry NCERT Solutions Ch 1 – Some Basic Concepts of Chemistry easy methods. NCERT Book for Class 11 Chemistry Chapter 13 Hydrocarbons is available for reading or download on this page. Our Revision Notes of Chemistry Class 11 touches upon Chemistry's fundamentals by defining Chemistry and discussing the different sections of Chemistry that students learn as part of their curriculum. Question 23. 1 molecule of ozone (O3) = 3 atoms of oxygen. Hence, A is the limiting reactant. Calcium carbonate reacts with aqueous HCl according to the reaction. (iii) 2 moles of carbon are burnt in 16 g of dioxygen. If the molecule is triatomic, what will be its atomic mass? 16 g of dioxygen can combine only with 0.5 mole of carbon.C02 produced again is equal to 22 g. Question 5. Answer: Question 5. Answer: (i) Reliability of measuring instrument. If you have any query regarding NCERT Solutions for Class 11 Chemistry at Work Chapter 1 Some Basic Concepts of Chemistry, drop a comment below and we will get back to you at the earliest. Answer:  Step I. Answer:  (i) According to the given reaction, 1 atom of A reacts with 1 molecule of B Its molecular formula is C6H12O6, while empirical formula is CH2O. Now, 1000 g of sugar cost = Rs 6, Question 5. Calculate the number of moles of N02  in 100 g of the mixture. What is the concentration of sugar (C12H22O11) in mol L -1 if its 20 g are dissolved in enough water to make a final volume up to 2 L? Why air is not always regarded as homogeneous mixture? What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl? To calculate mass of HCl in 25 mL of 0.75 m HCl (iii) Molecular mass of CH4= 12.01 amu + 4 (1.008 amu) = 16.042 amu. How are 0.5 ml of NaOH differents from 0.5 M of NaOH? Answer: Question 28. Chapter 3. Question 1.1 Calculate the molecular mass of the following : (i) H2O (ii) CO2 (iii) CH4 Calculate the number of atoms in each of the following: Molar mass of nitric acid HNO3= 1 + 14 + 48 = 63 gmol-1, Question 7. See Q3. These properties can be To calculate mass of CaC03reacting completely with 0.9125 g of HCl Answer: Step I. This chapter introduces students to the classification of matter based on the nature of their substances which include pure substances and mixtures and the properties of these matters and their measurement. The vapour density of a mixture of N02 and N204is 38.3 at 27°C. Question 14. Answer: Molar mass of water is 18 g/mol. Answer: (i) 2 (ii) 3 (iii) 4 (iv) 3 (v) 4 (vi) 5. Students may follow the links on the subtopics to access free study material on the associated concepts (prepared by chemistry subject experts for CBSE students). Chapter 6. Question 2. These’are in the ratio 1 : 2 : 1 : 5 which is a simple whole number ratio. (ii) Will any of the two reactants remain unreacted? Question 11. Free NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry solved by expert teachers from latest edition books and as per NCERT (CBSE) guidelines.Class 11 Chemistry Some basic Concepts of Chemistry NCERT Solutions and Extra Questions with Solutions to help you to revise complete Syllabus and Score More marks. Question 33. Calculate the number of moles in each of the following. (ii) Determine the molality of chloroform in the water sample. Short Answer Type Questions (iii) No limiting reagent. Some Basic Concepts of Chemistry Questions with Solutions to help you to revise complete Syllabus and Score More marks in your Class 11 Examinations. A volume of 10.0 L (measured at S.T.P.) How is empirical formula of a compound related to its molecular formula? NCERT Books chapter-wise Solutions (Text & Videos) are accurate, easy-to-understand and most helpful in Homework & Exam Preparations. Some basic concepts of Chemistry Class 11 NCERT Solutions are given to make your study simplistic and enjoyable at Vedantu. Chapterwise NCERT Solutions for Class 11 Chemistry NCERT Solutions for Class 11 Chemistry Chapter 1 – Some Basic Concepts of Chemistry . Answer:  S.I. Calculation of simplest whole number ratios of the elements. Question 17. How many oxygen atoms are there in 18 g of water? Question 8. Hence, the answer should have 4 significant. What is an atom according to Dalton’s atomic theory? Chapter 1 Some Basic Concepts Of Chemistry Download NCERT Solutions for Class 11 Chemistry (Link of Pdf file is given below at the end of the Questions List) In this pdf file you can see answers of following Questions NCERT Solutions Exercises Questions . Answer: Molecular formula = (Empirical formula)n where n is positive integer. (iii) If yes, which one and what would be its mass? 1 … Answer: Step 1. Answer: According to Dalton’s atomic theory, an atom is the ultimate particle of matter which cannot be further divided. How much copper can be obtained from 100 g of copper sulphate (CuSO4 )? (i) Express this in percent by mass Answer: The chemical equation for the reaction is: Question 4. Hence, A is the limiting reagent. Question 8. Question 6.Calculate: The NCERT Chemistry Books are based on the latest exam pattern and CBSE syllabus. Chapter 7. Answer:  Molecular mass of oxygen = 32 u. Gram molecular mass of NaCl = 23 + 35.5 = 58.5 g Now, 1000 g of NaCl cost = Rs 2 Convert the following into basic units: III. Answer: (a) Cost of table salt (NaCl) per mole It is also defined as follows. NCERT Solutions for Class 11 Science Chemistry Chapter 1 - Redox Reactions [FREE]. Question 1. Step II. (i) Number of moles of carbon atoms (ii) Number of moles of hydrogen atoms Hence,C0, (iii) Here again, dioxygen is the limiting reactant. Answer:  Mass percent of 69% means that 100 g of nitric acid solution contain 69 g of nitric acid by mass. Class 11 Chemistry NCERT - summary Chapter 1 | Unacademy Login Molar mass of sodium acetate is 82.0245 g mol-1, Answer: 0.375 M aqueous solution means that 1000 mL of the solution contain sodium acetate = 0.375 mole, Question 6. Answer: Question 10.In three moles of ethane (C2H6), calculate the following: Answer: 1 a.m.u. Question 9. Free PDF download of NCERT Solutions for Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry solved by Expert Teachers as per NCERT (CBSE) Book guidelines. NCERT Solutions for Class 11 Chemistry Chapter 1- Some Basic Concepts of Chemistry. Question 4. Answer: Pressure is the force (i.e., weight) acting per unit area But weight = mg. 16 g of dioxygen can combine only with 0.5 mole of carbon.C0, 0. NCERT Solutions of other subjects based on latest CBSE Curriculum for 2020 – 2021 is also available to free download. In this chapter, laws of chemical combination, Dalton’s atomic theory, mole concept, empirical and molecular … NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry are part of Class 11 Chemistry NCERT Solutions. How many significant figures are present in the following? IIT JEE Books; NEET Books; Study Notes. Given that the molar mass of the oxide is 159.8 g mol-1(Atomic mass: Fe = 55.85, O = 16.00 amu)Calculation of Empirical Formula. 2 mol of A will react with 2 mol of B. 50 M Na2C03 means 0.50 mol, i.e., 53 g Na, NCERT Solutions Class 11 Business Studies, NCERT Solutions Class 11 Entrepreneurship, NCERT Solutions Class 11 Indian Economic Development, NCERT Solutions Class 11 Computer Science, Chapter 1 Some Basic Concepts of Chemistry, Chapter 3 Classification of Elements and Periodicity in Properties, Chapter 4 Chemical Bonding and Molecular Structure, Chapter 12 Organic Chemistry: Some Basic Principles and Techniques, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, Periodic Classification of Elements Class 10, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10, Properties of Matter and their Measurement, Stoichiometry and Stoichiometric Calculations.

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