Question 2. Answer: Empirical formula mass of Fe203 = 2 x 55.85 + 3 x 16.00 = 159.7 g mol–1. (iv) 2.5 mol of B will react with 2.5 mol of A. (a) Mass of 2.5 gram atoms of magnesium, All exercise questions are solved by experts as per NCERT (CBSE) guidelines. Answer:  Molecular mass of oxygen = 32 u. Hence,C0, (iii) Here again, dioxygen is the limiting reactant. of carbon and oxygen atoms present in 11.2 litres of C02 at N.T.P. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. All Chapter 1 - Some Basic Concepts of Chemistry Exercises Questions with Solutions to help you to revise complete Syllabus and boost your score more in examinations. NCERT Solutions of other subjects based on latest CBSE Curriculum for 2020 – 2021 is also available to free download. KCl03 on heating decomposes to give KCl and 02. Answer: The balanced equation for the combustion of carbon in dioxygen/air is Calculate no. 1 molecule of ozone (O3) = 3 atoms of oxygen. Gram molecular mass of (C12H22O11) = 12 x 12 + 22 x 1 = 16 x 1= 144 + 22 + 176 = 342 g 200 molecules of B will react with 200 atoms of A and 100 atoms of A will be Calculate the number of moles in each of the following. Class 12; Class 11; Class 10; Class 9; Reference Books Solutions. Answer:  Mass percent of 69% means that 100 g of nitric acid solution contain 69 g of nitric acid by mass. NCERT Chemistry Chapter 1 Some Basic Concepts of Chemistry Notes for Class 11 by Selfstudys are best notes because these are prepared by experienced staff members. (iii) In the given addition, the least number of decimal places in the term is 4. Answer: Molar mass of water is 18 g/mol. Download subject-wise & chapter-wise NCERT Books PDF for Class 11 (All subjects) & prepare for UP board & CBSE Class 11 board exams with Jagranjosh.com. Answer: (i) 2 (ii) 3 (iii) 4 (iv) 3 (v) 4 (vi) 5. Answer: This is due to the presence of dust particles. To calculate mass of CaC03reacting completely with 0.9125 g of HCl Use the data given in the following table to calculate the molar mass of naturally occurring argon. (ii) Determine the molality of chloroform in the water sample. Chapterwise NCERT Solutions for Class 11 Chemistry NCERT Solutions for Class 11 Chemistry Chapter 1 – Some Basic Concepts of Chemistry . Number of oxygen atoms is 18 g of water = 6.02 x 1023. Question 9. Question 23. What is the number of significant figures in 1.050 x 104? Answer: Step 1. Before we get into Some Basic Concepts of Chemistry Class 11, it is vital to get the basic knowledge about the chapter. NCERT Book for Class 11 Chemistry Chapter 1 Some Basic Concepts Of Chemistry is available for reading or download on this page. The following data were obtained when dinitrogen and dioxygen react together to form compounds: .•. A compound on analysis was found to contain C = 34.6%, H = 3.85% and O = 61.55%. or 1 u = 1/12 th mass of an atom of carbon 12. .•. Question 11. Answer: Molar mass of Ar = 35.96755 x 0.00337 + 37.96272 x 0.00063 + 39.96924 x 0.99600 = 39.948 g mol-1. Define law of conservation of mass. Question 2. Thus, 2 volumes of H2 react with 1 volume of 02 to produce 2 volumes of water vapour. Answer: Question 5. or one ‘u’? Question 15. Answer: Question 7. What is the volume of 02 at N.T.P liberated by 0.1 mole of KCl03? These’are in the ratio 1 : 2 : 1 : 5 which is a simple whole number ratio. Observe each and every step to know the logic behind NCERT solutions of Chemistry Class 11 1st Chapter then you can able to answer any type of question in the exam. If you have any query regarding NCERT Solutions for Class 11 Chemistry at Work Chapter 1 Some Basic Concepts of Chemistry, drop a comment below and we will get back to you at the earliest. Question 1.1 Calculate the molecular mass of the following : (i) H2O (ii) CO2 (iii) CH4 4 HCl (aq) + Mn02 (s) ———–> 2 H2O (l) + MnCl2(aq) +Cl2(g). Question 2. Answer: Question 31. (v) 500.0 (vi) 2.0034 (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2(g) (Atomic masses: Au = 197, Na = 23, Li = 7, Cl = 35.5 amu). Answer: H2 and 02 react according to the equation. Therefore,C02 produced from the combustion of 1 mole of carbon = 44 g.(ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant. Its molecular formula is C6H12O6, while empirical formula is CH2O. NCERT Solutions for Class 11 Chemistry in PDF form to free download. How many significant figures are present in the following? I.Very Short Answer Type Questions Chapter 4. (i) 1 mole of carbon is burnt in air. How are 0.50 mol Na2C03 and 0.50 M Na2C03 different? To calculate mass of HCl in 25 mL of 0.75 m HCl What is an atom according to Dalton’s atomic theory? Question 12. Calculate the total number of electrons present in 1.6 g of methane. This chapter introduces students to the classification of matter based on the nature of their substances which include pure substances and mixtures and the properties of these matters and their measurement. (b) Cost of table sugar (C12H22O11) per mole Molality of a solution does not depend on temperature. Answer: The compound is glucose. Question 12. Hence, 10 volumes of H2 will react completely with 5 volumes of 02 to produce 10 volumes of water vapour. Calcium carbonate reacts with aqueous HCl according to the reaction. What do you understand by stoichiometric coefficients in a chemical equation? 2.5 gram atoms of Mg = 24 x 2.5 = 60g Answer: 1 mole of Mn02, i.e., 55 + 32 = 87 g Mn02 react with 4 moles of HCl, i.e., 4 x 36.5 g = 146 g of HCl. Free NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry solved by expert teachers from latest edition books and as per NCERT (CBSE) guidelines.Class 11 Chemistry Some basic Concepts of Chemistry NCERT Solutions and Extra Questions with Solutions to help you to revise complete Syllabus and Score More marks. 1 … State Avogadro’s law. Question 32. Question 29. Class 12; Class 11; Class 10; Class 9; Revision Notes. Question 14. Question 24. Here you will find both English and Hindi medium books to download. Short Answer Type Questions How many oxygen atoms are there in 18 g of water? How many grams of HCl react with 5.0 g of manganese dioxide? NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry are part of Class 11 Chemistry NCERT Solutions. The NCERT Class 11th Chemistry textbooks are well known for it’s updated and thoroughly revised syllabus. Answer:  1 mole of CuS04 contains 1 mole (1 g atom) of Cu, Molar mass of CuS04= 63.5 + 32 + 4 x 16 = 159.5 g mol-1, Thus, Cu that can be obtained from 159.5 g of CuS04 = 63.5 g. Question 8. 2.6 min = 2.6 min x conversion factor = 2.6 x 60s/1min= 156 s. Question 3. Answer: The chemical equation for the reaction is: Question 4. produced from the combustion of 1 mole of carbon = 44 g. (ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant. If ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour could be produced? A sample of drinking water was found to be severely contaminated with chloroform, CHCly supposed to be carcinogenic in nature. Express the following in scientific notation: Question 6. Chapter 6. Question 21. In the reaction, A + B2——> AB2, identify the limiting reagent, if any, in the following mixtures Students who are in Class 11 or preparing for any exam which is based on Class 11 Chemistry can refer NCERT Book for their preparation. This Class 11 Chemistry Index page contains all the topics that fall under each chapter of the class 11 chemistry syllabus as per the NCERT textbook. Writing the empirical formula of the compound. --Every substance has unique or characteristic properties. Moving with the chapter, students will find details about the nature of material and chemical laws of combination. You can also get NCERT Solutions for Class 11 Chemistry Chapter 1 PDF download from Vedantu’s website to assist you through the complete syllabus properly and obtain the best marks in your examinations. Question 1. Number of C02molecules in 11.2 litres. 50 M Na2C03 means 0.50 mol, i.e., 53 g Na2C03 are present in 1 litre of the solution. This Initial Chapter of Chemistry helps the students to understand the role played by Chemistry in different dimensions of life. (i) 300 atoms of A + 200 molecules ofB Answer: Question 3. Free Download. States of Matter . Express the following up to four significant figures. Hence, the answer should have 4 significant. What is one a.m.u. These properties can be left unreacted. The vapour density of a mixture of N02 and N204is 38.3 at 27°C. (i) 34.216 (ii) 10.4107 (iii) 0.04597 (iv) 2808 Define molality. Hence, the answer should have 4 significant figures. The density of water at room temperature is 1.0 g/mL. (Atomic mass of Mn = 55 u) Thermodynamics . (iii) Number of molecules of ethane For example, N2(g) + 3H2(g) ———–> 2 NH3(g) Question 7. Class 11 Chemistry NCERT - summary Chapter 1 | Unacademy Login of this welding gas is found to weigh 11.6 g. Calculate (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula. Question 8. Calculate the concentration of nitric acid in moles per litre in a sample which has a density 1.41 g mL-1 and the mass percent of nitric acid in it is being 69%. Pressure is determined as force per unit area of the surface. NCERT Solutions for Class 11 Science Chemistry Chapter 1 - Some Basic Concepts Of Chemistry [FREE]. The NCERT solutions for class 11 chemistry chapter 1 Some Basic Concepts of Chemistry are designed systematically by the chemistry subject experts. (ii) 2 mol A + 3 mol B (ii) Will any of the two reactants remain unreacted? .•. We hope the NCERT Solutions for Class 11 Chemistry Chapter 1 Some basic Concepts of Chemistry help you. Study Books. Answer: The digits in a properly recorded measurement are known as significant figures. Chapter 1. Calculate the empirical formula. (iii) 2 moles of carbon are burnt in 16 g of dioxygen. Molar mass of sodium acetate is 82.0245 g mol-1, Answer: 0.375 M aqueous solution means that 1000 mL of the solution contain sodium acetate = 0.375 mole, Question 6. 10 ml of a solution of NaCl containing KCl gave on evaporation 0.93 g of the mixed salt which gave 1.865 g of AgCl by reacting with AgN03solution. The empirical formula of the compound = C3H4O4. The Vapour Density of a gaseous element is 5 times that of oxygen under similar conditions. Calculate the molecular mass of the following: III. Structure of Atom . A flask P contains 0.5 mole of oxygen gas. (ii) 1 mole of C2H6 contains 6 moles of hydrogen atoms Some Basic Concepts of Chemistry . 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What is the S.I. Which one of the following will have largest number of atoms? These Basic Concepts of Chemistry Class 11 Chapter 1 Notes are made from the updated CBSE syllabus keeping the latest exam pattern in mind to keep students on the right track. Hence, the answer should have 3 significant figures. Answer: Four. Answer: Equal volumes of all gases under the conditions of same temperature and pressure contain the same number of molecules. NCERT Solutions for Class 11 Chemistry Chapter-1 Some Basic Concepts of Chemistry Law of chemical combination, Atomic & molecular mass, Mole concept, Determination of molecular formulae, Stoichiometry, Concentration terms.There are a large number of … The total numbers of figures in a number including the last digit whose value is uncertain is called number of significant figures. Answer: (a) Fixing the mass of dinitrogen as 28 g, masses of dioxygen combined will be 32,64, 32 and 80 g in the given four oxides. Chemical Bonding and Molecular Structure. (i) H20(ii) C02(iii) CH4, Answer:  (i) Molecular mass of H2O = 2(1.008 amu) + 16.00 amu=18.016 amu Answer: 0.5 ml of NaOH means 0.5 mole (20.0 g) of NaOH, 0.5M of NaOH means that 0.5 mole (20.0g) of NaOH are dissolved in 1L of its solution. unit of pressure, pascal, is as shown below:1 Pa = 1 Nm-2.If mass of air at sea level is 1034 g cm-2,calculate the pressure in pascal. What do you mean by significant figures? Some Basic Concepts of Chemistry Questions with Solutions to help you to revise complete Syllabus and Score More marks in your Class 11 Examinations. Answer: Step I. What is the SI unit of molarity? (iii) Molecular mass of CH4= 12.01 amu + 4 (1.008 amu) = 16.042 amu. Answer: We know that, 1 min = 60 s The S.I. Question 7. Our Revision Notes of Chemistry Class 11 touches upon Chemistry's fundamentals by defining Chemistry and discussing the different sections of Chemistry that students learn as part of their curriculum. Chapter 3. Calculate the amount of carbon dioxide that could be produced when (b) Gram atom in 1.4 grams of nitrogen (Atomic mass Mg = 24, N = 14) How are 0.5 ml of NaOH differents from 0.5 M of NaOH? 1000 mL of 0.75 M HCl contain HCl = 0.75 mol = 0.75 x 36.5 g = 24.375 g The simplest whole number ratios of the different elements are: C:H:O::3:4:4 Question 8. Free PDF download of NCERT Solutions for Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry solved by Expert Teachers as per NCERT (CBSE) Book guidelines. If the density of methanol is 0.793 kg L -1, what is its volume needed for making 2.5 L of its 0.25 M solution? Answer:  Step I. (iii) 100 atoms of A + 100 molecules ofB Answer:  (i) According to the given reaction, 1 atom of A reacts with 1 molecule of B Question 11. (ii) 1 mole of carbon is burnt in 16 g of dioxygen. (i) 0.0048 (v) 6.0012 (ii) 234,000 (iii) 8008 (iv) 500.0 (i) Express this in percent by mass Step II. Question 3. Question 1. Answer: Question 25. CaC03 (s) + 2HC1 (aq)———->CaCl2(aq) +C02(g) + H2O Answer: (i) Reliability of measuring instrument. Vedantu provides you with Class 11 Chemistry NCERT Solutions Chapter 1. (v) 2.5 mol of A will react with 2.5 mol of B. A volume of 10.0 L (measured at S.T.P.) Question 4. Question 14. Why air is not always regarded as homogeneous mixture?